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Express 1 + 2log_{10}3 in the form log_{10}q.

A. log_{10} 90

B. log_{10} 19

C. log_{10} 9

D. log_{10 }6

**Comments**

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1 + 2log_{10}3

But since log_{10}10 = 1, the above expression becomes:

log_{10}10 + 2log_{10}3

Also, 2log_{10}3 = log_{10}3^{2} = log_{10}9

Thus, the expression becomes:

log_{10}10 + log_{10}9

= log_{10}(10 x 9)

= log_{10} 90

**Ans A**

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