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How do i find the second derivative of esinx using product r...
calculus differentiation math
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How do i find the second derivative of esinx using product rule

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judziy
Asked by judziyrep:1.9K
University of Benin Nigeria
13 May 2020

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dp
james_mark
cos(x)e^sin(x) (cos(x) - tanx)
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dp
Wizardofdhakafahim,
please i need 3rd derivative
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james_mark
James_mark answeredrep:723
School not set Nigeria
05 December 2020
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y = esinx

dy/dx = cosx.esinx

To find the second derivative, we apply product rule,

V(du/dx) + U(dv/dx)

U = cosx

du/dx = -sinx

V = esinx

dv/dx = cosx.esinx

d2y/dx= esinx(-sinx) + cosx(cosx.esinx)

d2y/dx2 = cosx(cosx.esinx) - (sinx.esinx)

d2y/dx2 = esinx(cos2x - sinx)

OR

d2y/dx2 = cosx.esinx(cosx - tanx)

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