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What is the second derivative of e^sinx
math second-order-derivative differentiation calculus
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How do i find the second derivative of esinx using product rule

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judziy
Asked by judziyrep:909
University of Benin Nigeria
13 May 2020

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dp
james_mark
cos(x)e^sin(x) (cos(x) - tanx)




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james_mark
James_mark answeredrep:231
School not set Nigeria
19 July 2020
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y = esinx

dy/dx = cosx.esinx

To find the second derivative, we apply product rule,

V(du/dx) + U(dv/dx)

U = cosx

du/dx = -sinx

V = esinx

dv/dx = cosx.esinx

d2y/dx= esinx(-sinx) + cosx(cosx.esinx)

d2y/dx2 = cosx(cosx.esinx) - (sinx.esinx)

d2y/dx2 = esinx(cos2x - sinx)

OR

d2y/dx2 = cosx.esinx(cosx - tanx)

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