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if 23_{y} = 1111_{two} , find the value of y

A. 7

B. 6

C. 5

D. 4

**Comments**

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First, convert both sides to same base (in this case base 10)

2 x y^{1} + 3 x y^{0} = 1x2^{3} + 1x2^{2} + 1x2^{1} + 1x2^{0}

2y + 3 = 8 + 4 + 2 + 1

2y + 3 = 15

2y = 15 - 3

2y = 12

y = 12/2

y = 6

**Ans B**

Ans here is c

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@Kate11 You're wrong. Its B

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Correct

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