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A right circular cone has a volume of 24π cubic inches. If the height of the cone is 2 inches, what is the radius, in inches, of the base of the cone?

A) 2√3

B) 6

C) 12

D) 36

**Comments**

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The volume of a right circular cone is: v = 1/3 πr^{2}h

where v is the volume, r is radius and h is the height of the cone

v = 24π

h = 2

Substitute v = 24π and h = 2 into the equation above

24π = 1/3 π x r^{2} x 2

divide both sides by π, the equation becomes

24 = 1/3 x r^{2} x 2

multiply through by 3, the equation becomes

72 = 2r^{2}

divide both sides by 2

r^{2} = 36

Take the square root of both sides to remove square

r = √36

r = 6

**Ans B**

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