my college hive icon
Dy/dx = 4x - 3, y(1) = 0
JMAP math differential-equation
up
0
down

dy/dx = 4x - 3, y(1) = 0

A) y = 2x2 + x - 1

B) y = -x2 + x - 2

C) y = 2x2 + x + 1

D) y = 2x2 - 3x + 1

13 views
Edit Share Follow
judziy
Asked by judziyrep:213
University of Benin 25 June 2020

Comments





1 answer(s)

peter
Peter answeredrep:202
School not set 25 June 2020
up
0
down

dy/dx = 4x - 3

Multiply both sides by dx,

dy = (4x - 3) dx

Integrating both sides,

∫dy = ∫(4x - 3) dx

y = 4x2/2 - 3x + c

y = 2x2 - 3x + c ------------ eqn(1)

Where c is the integration constant.

Since y(1) = 0,

0 = 2(1)2 - 3(1) + c

0 = 2 - 3 + c

0  = -1 + c

Add 1 to both sides,

c = 1

Thus, eqn(1) becomes:

y = 2x2 - 3x + 1

Ans D

Improve answer Share
Comments






Your Answer

my college hive loader icon



Related Tags

JMAP

2 followers

141 questions

math

4 followers

843 questions

differential-equation

1 followers

8 questions