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A body is thrown up vertically with initial velocity 50m/s c...
Physics
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A body is thrown up vertically with initial velocity 50m/s calculate

i)time to reach maximum height

ii) maximum height reach

iii)the total time the body spent in the air

iv)the velocity with which the ball hit the ground

v)kinetic energy after 4s

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Ghana
04 October 2020

School not set Nigeria
05 October 2020
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I) from first equation of motion,  v = u + at

The above equation can be written as:

V = u - gt [because the ball travels against gravity]

V = 0

0 = u - gt

U = gt

g = 10m/s

50 = 10t

t = 50/10

t = 5 seconds

Ii) from third equation of motion, v2 = u2 + 2as.

The above equation can be written as:

V2 = u2 - 2gH [because the ball travels against gravity]

V = 0

0 = 502 - 2(10)H

2500 = 20H

H = 2500/20

H = 125m

Iii) total time spent in air = 2t

t = time to reach maximum height = 5

Total time spent in air = 2(5)

= 10 seconds

IV) from third equation of motion, v2 = u2 + 2as.

The above equation can be written as:

V2 = u2 + 2gH [because the ball travels with gravity]

U = 0

V2 = 2(10)(125)

V2 = 2500

V = 50m/s

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Ana,
Thanks a lot please you left the v
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james_mark
No... i don't know V
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Ana,
Okay I appreciate all your efforts.God bless u
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