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A ray of light travelling from glass into ethyl alcohol is incident at the boundary at an angle of incidence 30^{o}. Calculate the angle of refraction. [Refractive index of glass = 1.5; refractive index of ethyl alcohol = 1.36]

A. 27.0^{o}

B. 33.5^{o}

C. 51.7^{o}

D. 72.8^{o}

**Comments**

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from snell's law,

sinθ_{1}/sinθ_{2} = n_{2}/n_{1} -------------- eqn(1)

where,

n_{1}=incident index of ethyl = 1.36

n_{2}=refracted index of glass = 1.5

θ_{1 }= incident angle of ethyl = 30

θ_{2 }= refracted angle of glass

from eqn(1),

n_{1}sinθ_{1 }= n_{2}sinθ_{2}

sinθ_{2} = n_{1}sinθ_{1} / n_{2}

sinθ_{2} = 1.36sin(30) / 1.5

sinθ_{2} = 0.45333

θ_{2} = sin^{-1}(0.45333)

θ_{2 }= 27

**Answer: A**

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**Answer is A using snell's law**

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