0

Evaluate:

y/2x . z^{2 }when x = 6, y = 168, and z = 12.

[A] 336

[B] 24,192

[C] 1008

[D] 2016

Asked by peter•rep:202

School not set • 25 June 2020

School not set • 25 June 2020

**Comments**

Judziy answered•rep:213

University of Benin • 25 June 2020

University of Benin • 25 June 2020

0

y/2x . z^{2}

when x = 6, y = 168, and z = 12,

168/2(6) x 12^{2}

= 168/12 x 144

= 14 x 144

= 2016

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