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In the diagram, O is the center of the circle. SOQ is the diameter and ∠ SRP = 37^{o}. Find ∠PSQ.

A. 127

B. 65

C. 53

D. 37

**Comments**

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∠PQS = ∠SRP = 37

∠RQP = 90

∠RQS = 90 - ∠PQS

= 90 - 37

= 53

∠RQS = ∠PSQ = 53 [Alternate angles]

**Ans C**

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