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Given that y varies inversely as the square of x. If x =3 when y =100. Find the equation connecting x and y

A: yx^{2 }= 300

B: yx^{2} = 900

C: y=100x/9

D: y=900x^{2}

**Comments**

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y ∝ 1/x^{2}

y = k/x^{2} ------------- eqn(1)

where k is the proportionality constant

from eqn(1), k = yx^{2} ------------ eqn(2)

if x = 3 and y = 200,

k = 100(3)^{2}

= 900

Therefore, the equation connecting x and y will be:

from eqn(1),

y = 900/x^{2}

yx^{2} = 900

**Answer: B**

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