Given that y varies inversely as the square of x. If x =3 when y =100. Find the equation connecting x and y
A: yx2 = 300
B: yx2 = 900
C: y=100x/9
D: y=900x2
Comments
y ∝ 1/x2
y = k/x2 ------------- eqn(1)
where k is the proportionality constant
from eqn(1), k = yx2 ------------ eqn(2)
if x = 3 and y = 200,
k = 100(3)2
= 900
Therefore, the equation connecting x and y will be:
from eqn(1),
y = 900/x2
yx2 = 900
Answer: B
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