mycollegehive
Find the equation of a straight line passing through the point (1, -5) and having gradient 3/4
A. 3x+4y-23=0
B. 3x+4y+23=0
C. 3x-4y+23=0
D. 3x-4y-23=0
Share
Follow
Comments
From the point-slope form of straight line equation,
y - y1 = m(x - x1)
m = 3/4
y1 = -5
x1 = 1
y - (-5) = 3/4 (x - 1)
y + 5 = 3x/4 - 3/4
multiply through by 4
4y + 20 = 3x - 3
3x - 4y - 3 - 20 = 0
3x - 4y -23 = 0
Ans D
Share
Your Answer
How to insert math formulas/equations
button on the menu bar
