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Find the equation of a straight line passing through the poi...
waec-2019 ssce-exam-2019 waec-mathematics-2019 math coordinate-geometry 0 Find the equation of a straight line passing through the point (1, -5) and having gradient 3/4

A. 3x+4y-23=0

B. 3x+4y+23=0

C. 3x-4y+23=0

D. 3x-4y-23=0

277 views Share Follow Asked by peterrep:1.7K
University of Lagos Nigeria
22 April 2020

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### 1 answer(s)

Advertisement (continue below) Judziy answeredrep:1.9K
University of Benin Nigeria
05 December 2020 0 From the point-slope form of straight line equation,

y - y= m(x - x1)

m = 3/4

y1 = -5

x1 = 1

y - (-5) = 3/4 (x - 1)

y + 5 = 3x/4 - 3/4

multiply through by 4

4y + 20 = 3x - 3

3x - 4y - 3 - 20 = 0

3x - 4y -23 = 0

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