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Find the equation of a straight line passing through the point (1, -5) and having gradient 3/4

A. 3x+4y-23=0

B. 3x+4y+23=0

C. 3x-4y+23=0

D. 3x-4y-23=0

**Comments**

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From the point-slope form of straight line equation,

y - y_{1 }= m(x - x_{1})

m = 3/4

y_{1} = -5

x_{1} = 1

y - (-5) = 3/4 (x - 1)

y + 5 = 3x/4 - 3/4

multiply through by 4

4y + 20 = 3x - 3

3x - 4y - 3 - 20 = 0

3x - 4y -23 = 0

**Ans D**

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