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If log_{x}2 = 0.3, evaluate log_{x}8

A. 2.4

B. 1.2

C. 0.9

D. 0.6

**Comments**

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log_{x}2 = 0.3

log_{x}8 = ?

log_{x}8 = log_{x}2^{3}

log_{x}8 = 3log_{x}2

substituting log_{x}2 = 0.3

log_{x}8 = 3(0.3)

log_{x}8 = 0.9

**Ans C**

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