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Two cars A and B with velocity 280m/s and 80m/s respectively...
Physics
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Two cars A and B with velocity 280m/s and 80m/s respectively.Car B leaves point X 6:00am and car A also leaves the same point 6:40am . Calculate the distance between the two cars after

i)hr

ii)where do you think car A will overtake car B

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Ana
Asked by Anarep:53
Ghana
04 October 2020

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james_mark
James_mark answeredrep:694
School not set Nigeria
21 October 2020
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Let sa and sb be the distance of car A and B respectively 

va = sa/ta

sa = vata

sb = vbtb

I) the distance between both cars = sa - sb

= vata - vbtb ---------- eqn(1)

Assuming 6:40 am as the reference time, 

for car A after 1 hour (3600 seconds),

ta = 3600 - 0 = 3600 seconds

For car B, which is 40 minutes (2400 seconds) ahead 

t= 3600 + 2400 = 6000 seconds

from eqn(1),

= 280(3600) - 80(6000)

= 528,000 m

= 528km

 

Ii) car A overtakes car B when sa = sb

vata = vbtb

ta = t

tb = t + 40

280t = 80(t + 40)

280t = 80t + 3200

280t - 80t = 3200

200t = 3200

t = 3200/200

t = 16 minutes (or 960 seconds)

 

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