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Find the value of x for which 32_{four} = 22_{x}

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32_{four} = 22_{x}

Convert both sides to base 10

3*4^{1} + 2*4^{0} = 2*x^{1} + 2*x^{0}

3*4 + 2*1 = 2*x + 2*1

12 + 2 = 2x + 2

14 = 2x + 2

2x = 14 - 2

2x = 12

x = 12/2

x = 6

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