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A 500N box rests on a horizontal floor. A constant horizontal force is exerted on the box so that it moves through 8m. If the coefficient of kinetic friction between the floor and the box is 0.22, calculate the work done on the box.

A. 880J

B. 440J

C. 400J

D. 110J

**Comments**

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F_{r} is the force applied on the box which causes it to move.

F is the force exerted by th box

μ is the coefficient of friction.

F_{r} = 0.22 x 500

= 110N

Therefore, the work done, W = F_{r} x d

where,

F_{r} is the force applied on the box which causes it to move and d is the distance moved

W = 110 x 8

= 880J

**Answer: A**

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