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If 2a = √64 and b/a=3, evaluate a2 + b2
waec-2019 ssce-exam-2019 waec-mathematics-2019 math 0 If 2a = √64 and b/a=3, evaluate a2 + b2

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17 July 2020 Vikky,
Hello
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26 June 2021 0 2a = √64 ----------- eqn(1)

b/a=3 ------------ eqn(2),

From eqn(1),

2a = 8

2a = 23

From laws of indices,

a = 3

Substitute the value of a into eqn(2)

b/3 = 3

b = 3 × 3

b = 9

Therefore,

a2 + b2 = 32 + 92

= 9 + 81

= 90 Share University of Benin Nigeria
06 February 2021 0 2a = √64 ----------- eqn(1)

b/a=3 -------- eqn(2)

from eqn(2), multiply both sides by a,

b = 3a ---------- eqn(3)

Also, from eqn(1), 2a = 8

divide both sides by 2,

a = 8/2

a = 4

substitute a = 4 into eqn(3)

b = 3(4)

b = 12

Thus, a2 + b2 = 42 + 122

= 16 + 144

= 160 Share Johnny,
Please how did you get a=4, remember the a is the square of the 2, not 2a
1 likes, 0 dislikes

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