mycollegehive
Given the list of scores as:
2, 3, 4, 5, 3, 1
Mean Deviation = ∑|x − μ| / n
where n is the number of terms in the list and μ is the mean of the list
n = 6
μ = ∑(x) / n
= (2 + 3 + 4 + 5 + 3 + 1)/6
= 18/6
= 3
Mean Deviation = (|2 − 3| + |3 - 3| + |4 - 3| + |5 - 3| + |3 - 3| + |1 - 3|) / 6
= (|-1| + |0| + |1| + |2| + |0| + |-2|)/6
= (1 + 1 + 2 + 2)/6
= 6/6
= 1
Thus, the mean deviation is 1
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