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Given the list of scores as:

2, 3, 4, 5, 3, 1

Mean Deviation = ∑|x − μ| / n

where n is the number of terms in the list and μ is the mean of the list

n = 6

μ = ∑(x) / n

= (2 + 3 + 4 + 5 + 3 + 1)/6

= 18/6

= 3

Mean Deviation = (|2 − 3| + |3 - 3| + |4 - 3| + |5 - 3| + |3 - 3| + |1 - 3|) / 6

= (|-1| + |0| + |1| + |2| + |0| + |-2|)/6

= (1 + 1 + 2 + 2)/6

= 6/6

= 1

Thus, the mean deviation is 1

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