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If 2^x - 1 = (√2)^2 and 3^y- 2 = (√3)^4 then, what is y/x
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If 2x - 1 = (√2)and

3y- 2 = (√3)4 then,

what is y/x

I came across this question and i saw that the answer is 2 but i don't know how

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Asked by rep:2

25 February 2020

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1 answer(s)

judziy
Judziy answeredrep:909
University of Benin Nigeria
19 July 2020
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First,remove the square root with a square. That is

2x - 1 = 2

3y- 2 = 32

The next step is to linearize the equation by multiplying through with log.

The equation becomes:

log(2)x - 1 = log(2)

(x - 1)log(2) = log(2)

Dividing through by log(2)

(x - 1) = 1

x = 2

log(3)y- 2 = log(3)2

(y - 2)log(3) = 2log(3)

Dividing through by log(3)

y - 2 = 2

y = 2

Therefore, y/x = 4/2 = 2

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