Area of the segment (shaded portion) = Area of sector ACB - Area of triangle ACB
∠ACB = 90 [because it's a right angle].
Area of sector ACB = 1/2 (length of arc x radius)
length of arc = θ/360 x 2πr
Area of sector ACB = 1/2 (θ/360 x 2πr x r)
= 1/2 (θ/360 x 2πr2)
= θ/360 x πr2
where r is the radius.
r = 14cm
Thus, area of sector ACB = 90/360 x π x (14)2
but, π = 22/7
Area of sector ACB = 49 x 22/7
Area of triangle ACB = 1/2 base x height
= 1/2 x 14 x 14
Therefore, area of the segment = 154 - 98
= 56 cm2