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d/dx [log(4x^{3 }- 2x)] is equal to

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y = [log(4x^{3} - 2x)]

let u = 4x^{3} - 2x

y = log(u)

du/dx = 12x^{2} - 2

dy/du = 1/u

Thus, dy/du * du/dx = dy/dx = 1/u * 12x^{2} - 2

= (12x^{2} - 2) / u

but u = 4x^{3} - 2x

Therefore, dy/dx = (12x^{2} - 2) / (4x^{3} - 2x)

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