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If log10(6x-4) - log102 = 1, solve for x  A:  2&n...
waec-2018 ssce-exam-2018 waec-mathematics-2018 math
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If log10(6x-4) - log102 = 1, solve for x 

A:  2 

B:  3 

C:  4 

D:  5

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alberteinstein
Asked by alberteinsteinrep:269
School not set Nigeria
01 September 2020

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peter
Peter answeredrep:1.7K
University of Lagos Nigeria
01 September 2020
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log10(6x-4) - log102 = 1 --------------- eqn(1)

but log1010 = 1

Therefore, eqn(1) becomes:

log10(6x-4) - log102 = log1010 ------------ eqn(2)

Also, from the rules of solving logarithm, log10(6x-4) - log102 becomes: log10[(6x-4)/2] 

eqn(2) becomes:

log10[(6x-4)/2] = log1010

divide both sides by log10

(6x-4)/2 = 10

6x - 4 = 20

6x = 20 + 4

6x = 24

x = 24/6

x = 4

Answer: C

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