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E^2x - e^x = 15
Math
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e2x - ex = 15

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Joshua43
Asked by Joshua43rep:65
Nigeria
14 September 2020

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james_mark
James_mark answeredrep:568
School not set Nigeria
17 September 2020
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e2x - ex = 15

(ex)2 - ex = 15

let u = ex ------------- eqn(1)

u2 - u - 15 = 0

solving the above quadratic equation, we have:

u = 4.4051 or u = -3.4015

since only positive values are valid, -3.4015 is ignored. Thus,

u = 4.4051

from eqn(1), 

4.4051 = ex

multiply both sides by ln to remove e on the right hand side

ln(4.4051) = ln(ex)

ln(4.4051) = x

x = 1.48

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