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Evaluate (log39 - log28)/log39 A. -1/3 B. 1/2 C. 1/3 D. ...
waec-mathematics-2019 ssce-exam-2019 waec-2019 math logarithm
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Evaluate (log39 - log28)/log39

A. -1/3

B. 1/2

C. 1/3

D. -1/2

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peter
Asked by peterrep:1.8K
University of Lagos Nigeria
04 May 2020

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judziy
Judziy answeredrep:2.0K
University of Benin Nigeria
31 August 2020
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first, simplify

log39 = log332 = 2log33

since, logab = (log10b)/(log10a)

similarly, logaa = (log10a)/(log10a) = 1

Therefore, log33 = (log103)/(log103) = 1

log39 =2(1) = 2

log28 = log223 = 3log22

log22 = 1

log28 = 3(1) = 3

(log39 - log28)/(log39) = (2 - 3)/2

= -1/2

Ans D

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