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If x = 2 and y = -3, what is the value of 2x^{2} - 3xy - 2y^{2} ?

1) -20

2) -2

3) 8

4) 16

**Comments**

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2x^{2} - 3xy - 2y^{2}

When x = 2 and y = -3, the expression becomes:

2(2)^{2} - 3(2)(-3) - 2(-3)^{2}

=2(4) + 18 - 2(9)

= 8 + 18 - 18

= 8

**Ans 3**

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